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10v^2-85v+75=0
a = 10; b = -85; c = +75;
Δ = b2-4ac
Δ = -852-4·10·75
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-65}{2*10}=\frac{20}{20} =1 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+65}{2*10}=\frac{150}{20} =7+1/2 $
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